Question

chemistry 20 stoichiometry quiz
name: ebtesari
numeric response
numeric response

1. what mass of water vapour is produced when 0.960 mol of hydrogen gas burns completely in excess oxygen gas?

(record your answer in the numerical - response section below.)
your answer: □□□□

Explanation:

Step1: Write the balanced chemical equation

$2H_2(g)+O_2(g)
ightarrow 2H_2O(g)$

Step2: Determine the mole - ratio

From the equation, the mole - ratio of $H_2$ to $H_2O$ is 1:1. So, if $n(H_2) = 0.960$ mol, then $n(H_2O)=0.960$ mol.

Step3: Calculate the molar mass of water

The molar mass of $H_2O$, $M(H_2O)=(2\times1.01 + 16.00)$ g/mol = 18.02 g/mol.

Step4: Calculate the mass of water

Using the formula $m = n\times M$, where $n = 0.960$ mol and $M = 18.02$ g/mol. So, $m(H_2O)=0.960\ mol\times18.02\ g/mol = 17.3$ g.

Answer:

17.3