Question

a chemistry student needs 55.0 ml of ethanolamine for an experiment. by consulting the crc handbook of chemistry and physics, the student discovers that the density of ethanolamine is 1.02 g·cm⁻³. calculate the mass in g of ethanolamine the student should weigh out. round your answer to 3 significant digits.

Explanation:

Step1: Recall the density formula

The formula for density is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. We need to solve for $m$, so we can rearrange the formula to $m =
ho\times V$.

Step2: Convert volume units (if necessary)

We know that $1\space mL = 1\space cm^3$, so the volume $V = 55.0\space mL=55.0\space cm^3$. The density $
ho = 1.02\space g\cdot cm^{-3}$.

Step3: Calculate the mass

Substitute the values of $
ho$ and $V$ into the formula $m=
ho\times V$. So $m = 1.02\space g\cdot cm^{-3}\times55.0\space cm^3$.
Calculating the product: $1.02\times55.0 = 56.1$.

Answer:

56.1