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Question
chemistry - unit 1 test
- cubic centimeter is a unit used to measure
a. mass b. area c. weight d. volume
- what property of matter does not change even though the appearance may change?
a. mass b. area c. shape d. volume
- when matter changes from liquid to solid, phase energy...
a. increases b. decreases c. stays the same
- when matter increases in temperature, thermal energy...
a. increases b. decreases c. stays the same
- above is a cylinder containing water. an object with a mass of 21g and a volume of 15 cm³ is lowered into the water. sketch the object and the new water level in the cylinder on the right.
- use the dimensional - analysis method to make the following conversions (be sure to keep the appropriate number of sfs)
a. 340 ml x = liters
b. 200.5 g x = mg
c. 1.52×10⁸ mm x x = km
Step1: Answer question 1
Cubic centimeter measures volume.
Step2: Answer question 2
Mass is the property that doesn't change with appearance change.
Step3: Answer question 3
When matter changes from liquid to solid, phase energy decreases.
Step4: Answer question 4
When matter increases in temperature, thermal energy increases.
Step5: Answer question 5
First, find the density of the object: $
ho=\frac{m}{V}=\frac{21g}{15cm^{3}} = 1.4g/cm^{3}$. Since the density of water is approximately $1g/cm^{3}$, the object will sink. The initial water - level is not given, assume it is at $30mL$ (from the cylinder drawing). The volume of the object is $15cm^{3}=15mL$. The new water - level will be at $30 + 15=45mL$. Sketch the object at the bottom of the cylinder and mark the new water - level at $45mL$.
Step6: Answer question 6a
Use the conversion factor $1L = 1000mL$. So, $340mL\times\frac{1L}{1000mL}=0.34L$.
Step7: Answer question 6b
Use the conversion factor $1g = 1000mg$. So, $200.5g\times\frac{1000mg}{1g}=200500mg$.
Step8: Answer question 6c
Use the conversion factors $1km = 10^{6}mm$. So, $1.52\times10^{8}mm\times\frac{1m}{1000mm}\times\frac{1km}{1000m}=152km$.
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- d. volume
- a. mass
- b. decreases
- a. increases
- Sketch object at bottom, new water - level at 45mL (assuming initial level at 30mL)
- a. $340mL\times\frac{1L}{1000mL}=0.34L$
b. $200.5g\times\frac{1000mg}{1g}=200500mg$
c. $1.52\times10^{8}mm\times\frac{1m}{1000mm}\times\frac{1km}{1000m}=152km$