Question

classify each reactant and product in the reaction as an acid or base according to the brønsted theory. \\( \ce{hno3 + (ch3)3co- <=> (ch3)3coh + no3-} \\)

acid

base

answer bank
\\( \ce{(ch3)3coh} \\) \\( \ce{(ch3)3co-} \\) \\( \ce{no3-} \\) \\( \ce{hno3} \\)

Explanation:

Per Brønsted theory, acids donate H⁺, bases accept H⁺.

1. $\text{HNO}_3$ donates an H⁺ to become $\text{NO}_3^-$ → Acid.
2. $\text{(CH}_3\text{)}_3\text{CO}^-$ accepts an H⁺ to become $\text{(CH}_3\text{)}_3\text{COH}$ → Base.
3. $\text{(CH}_3\text{)}_3\text{COH}$ is the conjugate acid (formed when base accepts H⁺) → Acid.
4. $\text{NO}_3^-$ is the conjugate base (formed when acid donates H⁺) → Base.

Answer:

Acid:

$\text{HNO}_3$, $\text{(CH}_3\text{)}_3\text{COH}$

Base:

$\text{(CH}_3\text{)}_3\text{CO}^-$, $\text{NO}_3^-$