Question

the coefficient for the d - block is always
so on the 4th row of the periodic table, you would not write 4d but would write
the f block is always ____ numbers less than the s block - so if you left off on 6s when writing a configuration, the first f block starts at ______
try it out! see if you can write an electron configuration for aluminum. (al)
this will not be graded for accuracy. i will use it see how far you get it so far.
before you start: what is the atomic number of aluminum? ________
longhand configuration:________
shorthand configuration:________

Explanation:

Step1: Determine atomic number

Aluminum has an atomic number of 13.

Step2: Write long - hand electron configuration

Electrons fill orbitals in the order 1s < 2s < 2p < 3s < 3p. For 13 electrons, the long - hand configuration is 1s²2s²2p⁶3s²3p¹.

Step3: Write shorthand electron configuration

The noble gas before aluminum is neon (Ne) which has 10 electrons. So the shorthand configuration is [Ne]3s²3p¹.

Answer:

Atomic number of aluminum: 13
Longhand Configuration: 1s²2s²2p⁶3s²3p¹
Shorthand Configuration: [Ne]3s²3p¹