Question

compare the total mass of the reactants to the total mass of the products. what choice demonstrates the law of conservation of mass? 18 g h₂o + 28 g c₂h₄ → 55 g ch₃ch₂oh 102 g s + 102 g o₂ → 204 g so₂ 31 g o₂ + 49 g mg → 81 g mgo 23 g na + 71 g cl₂ → 92 g nacl

Explanation:

Step1: Calculate reactant mass (Option1)

$18\ \text{g} + 28\ \text{g} = 46\ \text{g}$

Step2: Compare to product mass (Option1)

$46\ \text{g}
eq 55\ \text{g}$

Step3: Calculate reactant mass (Option2)

$102\ \text{g} + 102\ \text{g} = 204\ \text{g}$

Step4: Compare to product mass (Option2)

$204\ \text{g} = 204\ \text{g}$

Step5: Calculate reactant mass (Option3)

$31\ \text{g} + 49\ \text{g} = 80\ \text{g}$

Step6: Compare to product mass (Option3)

$80\ \text{g}
eq 81\ \text{g}$

Step7: Calculate reactant mass (Option4)

$23\ \text{g} + 71\ \text{g} = 94\ \text{g}$

Step8: Compare to product mass (Option4)

$94\ \text{g}
eq 92\ \text{g}$

Answer:

B. $102\ \text{g S} + 102\ \text{g O}_2
ightarrow 204\ \text{g SO}_2$