Question

complete the balanced dissociation equation for the compound below in aqueous solution. if the compound does not dissociate, write nr after the reaction arrow. be sure to include the proper phases for all species within the reaction. cabr₂(s)→

Explanation:

Step1: Identify dissociation products

Calcium bromide ($CaBr_2$) dissociates into calcium ions ($Ca^{2 + }$) and bromide ions ($Br^-$) in aqueous solution.
$CaBr_2(s)
ightarrow Ca^{2+}(aq)+ 2Br^-(aq)$

Step2: Check charge - balance

The calcium ion has a + 2 charge and there are two bromide ions each with a - 1 charge. So, the overall charge on the left - hand side (0 for the neutral solid) is equal to the overall charge on the right - hand side ($+2+(2\times(- 1)) = 0$).

Answer:

$CaBr_2(s)
ightarrow Ca^{2+}(aq)+ 2Br^-(aq)$