Question

2: complete the chart below.

hyphen notation	nuclear notation	atomic #	mass #	# of p⁺	# of n⁰	# of e⁻
	³⁷k	5
			11	5
				47	60
	²³⁸u
oxygen-17
			108		61
			129	52
			19	9

Explanation:

Step1: Recall atomic - related concepts

Atomic number ($Z$) is equal to the number of protons ($p^{+}$). Mass number ($A$) is the sum of protons and neutrons ($n^{0}$), i.e., $A=p^{+}+n^{0}$. In a neutral atom, the number of electrons ($e^{-}$) is equal to the number of protons. Nuclear notation is written as $^{A}_{Z}X$, where $X$ is the chemical symbol.

Step2: For Uranium - 235

Uranium has an atomic number of 92. So, for Uranium - 235:
Atomic number ($Z$) = 92, Mass number ($A$)=235, number of protons ($p^{+}$)=92, number of neutrons ($n^{0}$)=235 - 92=143, number of electrons ($e^{-}$)=92 (neutral atom). Nuclear notation is $^{235}_{92}U$.

Step3: For $^{37}K$

Potassium ($K$) has an atomic number of 19. Mass number ($A$) = 37, number of protons ($p^{+}$)=19, number of neutrons ($n^{0}$)=37 - 19 = 18, number of electrons ($e^{-}$)=19 (neutral atom). Hyphen notation is Potassium - 37.

Step4: For the element with $p^{+}=11$

The element with 11 protons is Sodium ($Na$). Atomic number ($Z$)=11, if $p^{+}=11$ and $n^{0}=5$, then mass number ($A$)=11 + 5=16. Number of electrons ($e^{-}$)=11 (neutral atom). Hyphen notation is Sodium - 16, nuclear notation is $^{16}_{11}Na$.

Step5: For the element with $p^{+}=47$ and $n^{0}=60$

Atomic number ($Z$)=47 (equal to number of protons), mass number ($A$)=47+60 = 107. The element with atomic number 47 is Silver ($Ag$). Number of electrons ($e^{-}$)=47 (neutral atom). Hyphen notation is Silver - 107, nuclear notation is $^{107}_{47}Ag$.

Step6: For $^{238}U$

Uranium has an atomic number of 92. Mass number ($A$)=238, number of protons ($p^{+}$)=92, number of neutrons ($n^{0}$)=238 - 92=146, number of electrons ($e^{-}$)=92 (neutral atom). Hyphen notation is Uranium - 238.

Step7: For Oxygen - 17

Oxygen has an atomic number of 8. Atomic number ($Z$)=8, mass number ($A$)=17, number of protons ($p^{+}$)=8, number of neutrons ($n^{0}$)=17 - 8 = 9, number of electrons ($e^{-}$)=8 (neutral atom). Nuclear notation is $^{17}_{8}O$.

Step8: For the element with $A = 108$ and $n^{0}=61$

If $A = 108$ and $n^{0}=61$, then number of protons ($p^{+}$)=108 - 61=47. The element with atomic number 47 is Silver ($Ag$). Atomic number ($Z$)=47, number of electrons ($e^{-}$)=47 (neutral atom). Hyphen notation is Silver - 108, nuclear notation is $^{108}_{47}Ag$.

Step9: For the element with $A = 129$ and $p^{+}=52$

Atomic number ($Z$)=52 (equal to number of protons), number of neutrons ($n^{0}$)=129 - 52=77. The element with atomic number 52 is Tellurium ($Te$). Number of electrons ($e^{-}$)=52 (neutral atom). Hyphen notation is Tellurium - 129, nuclear notation is $^{129}_{52}Te$.

Step10: For the element with $A = 19$ and $p^{+}=9$

Atomic number ($Z$)=9 (equal to number of protons), number of neutrons ($n^{0}$)=19 - 9 = 10. The element with atomic number 9 is Fluorine ($F$). Number of electrons ($e^{-}$)=9 (neutral atom). Hyphen notation is Fluorine - 19, nuclear notation is $^{19}_{9}F$.

Answer:

Hyphen Notation	Nuclear Notation	Atomic #	Mass #	# of $p^{+}$	# of $n^{0}$	# of $e^{-}$
Potassium - 37	$^{37}_{19}K$	19	37	19	18	19
Sodium - 16	$^{16}_{11}Na$	11	16	11	5	11
Silver - 107	$^{107}_{47}Ag$	47	107	47	60	47
Uranium - 238	$^{238}_{92}U$	92	238	92	146	92
Oxygen - 17	$^{17}_{8}O$	8	17	8	9	8
Silver - 108	$^{108}_{47}Ag$	47	108	47	61	47
Tellurium - 129	$^{129}_{52}Te$	52	129	52	77	52
Fluorine - 19	$^{19}_{9}F$	9	19	9	10	9