Question

complete this equation that represents the process of nuclear fission.
( ce{_{94}^{239}pu + _{0}^{1}n
ightarrow _{b}^{a}ba + _{38}^{91}sr + 3_{0}^{1}n} )
a:

b:

Explanation:

Step1: Conserve Mass Number (A)

Mass number on left: \(239 + 1 = 240\)
Mass number on right: \(A + 91 + 3\times1 = A + 94\)
Set equal: \(A + 94 = 240\) → \(A = 240 - 94 = 146\)

Step2: Conserve Atomic Number (B)

Atomic number on left: \(94 + 0 = 94\)
Atomic number on right: \(B + 38 + 3\times0 = B + 38\)
Set equal: \(B + 38 = 94\) → \(B = 94 - 38 = 56\)

Answer:

A: \(146\)
B: \(56\)