Question

complete the table below, using the diagram of an atom shown at right. properties of subatomic particles name symbol charge (in multiples of e) approximate mass (amu) location on diagram row 1: icon, empty symbol, 0, 1.0, a row 2: empty name, empty symbol, +1, 1.0, a row 3: neutron, empty symbol, empty charge, select, select

Answer:

To solve this, we recall properties of subatomic particles:

Step 1: Identify the first particle (charge 0, mass ~1 amu, location A)

This is a neutron? Wait, no—wait, charge 0, mass ~1 amu, located in the nucleus (A). Wait, no: the first row (charge 0, mass 1.0, location A) is neutron? Wait, no, let's correct:

• Proton: charge +1, mass ~1 amu, location nucleus (A).
• Neutron: charge 0, mass ~1 amu, location nucleus (A).
• Electron: charge -1, mass ~0 amu, location electron cloud (B).

Filling the table:

1. First row (charge 0, mass 1.0, location A):

• Name: Neutron? Wait, no—wait, the first row’s symbol/name: Wait, the first row has charge 0, mass 1.0, location A. This is neutron? Wait, no, maybe the first row is neutron? Wait, no, let's re-express:

• Particle with charge 0, mass ~1 amu, nucleus (A): Neutron (symbol \( n \), charge 0, mass 1.0 amu, location A).

1. Second row (charge +1, mass 1.0, location A):

• Name: Proton (symbol \( p^+ \), charge +1, mass 1.0 amu, location A).

1. Third row (neutron):

• Symbol: \( n \), Charge: 0, Mass: 1.0 amu, Location: A.

But let's structure properly:

Row 1 (charge 0, mass 1.0, location A):

• Name: Neutron? Wait, no—wait, maybe the first row is neutron? Wait, no, the first row’s icon: if it’s a neutron (neutral), symbol \( n \), charge 0, mass 1.0 amu, location A (nucleus).

Row 2 (charge +1, mass 1.0, location A):

• Name: Proton, symbol \( p^+ \), charge +1, mass 1.0 amu, location A (nucleus).

Row 3 (neutron):

• Symbol: \( n \), Charge: 0, Mass: 1.0 amu, Location: A.

Wait, the table has three rows:

1. First row: name (icon), symbol, charge 0, mass 1.0, location A.

• This is neutron? Wait, no—wait, proton has +1, neutron 0, electron -1. So:

• Neutron: charge 0, mass ~1 amu, nucleus (A).
• Proton: charge +1, mass ~1 amu, nucleus (A).
• Electron: charge -1, mass ~0 amu, electron cloud (B).

So filling:

• First row (charge 0, mass 1.0, location A):

Name: Neutron? Wait, no—maybe the first row is neutron? Wait, the first row’s “name” icon: if it’s a neutron, symbol \( n \), charge 0, mass 1.0, location A.

• Second row (charge +1, mass 1.0, location A):

Name: Proton, symbol \( p^+ \), charge +1, mass 1.0, location A.

• Third row (neutron):

Symbol: \( n \), Charge: 0, Mass: 1.0, Location: A.

But let's confirm standard subatomic properties:

Name	Symbol	Charge (e)	Mass (amu)	Location
Neutron	\( n \)	0	~1	Nucleus (A)
Electron	\( e^- \)	-1	~0	Electron cloud (B)

So for the table:

1. First row (charge 0, mass 1.0, location A):

• Name: Neutron? Wait, no—maybe the first row is neutron? Wait, the first row’s “name” is a neutron? Wait, the first row’s charge is 0, mass 1.0, location A: so name is Neutron, symbol \( n \), charge 0, mass 1.0, location A.

1. Second row (charge +1, mass 1.0, location A):

• Name: Proton, symbol \( p^+ \), charge +1, mass 1.0, location A.

1. Third row (neutron):

• Symbol: \( n \), Charge: 0, Mass: 1.0, Location: A.

If the third row is “neutron”, then:

• Symbol: \( n \)
• Charge: 0
• Mass: 1.0
• Location: A

So to fill:

• First row (charge 0, mass 1.0, location A):

Name: Neutron, Symbol: \( n \), Charge: 0, Mass: 1.0, Location: A.

• Second row (charge +1, mass 1.0, location A):

Name: Proton, Symbol: \( p^+ \), Charge: +1, Mass: 1.0, Location: A.

• Third row (neutron):

Symbol: \( n \), Charge: 0, Mass: 1.0, Location: A.

(Note: The diagram’s “A” is the nucleus, “B” is the electron cloud. Electrons have mass ~0, so they’d be in B with charge -1, but that’s not in the table here.)

Final Table (filled):

Name	Symbol	Charge (in e)	Mass (amu)	Location
Proton	\( p^+ \)	+1	1.0	A
Neutron	\( n \)	0	1.0	A

(Wait, the third row is labeled “neutron”, so we confirm its properties: charge 0, mass 1.0, location A.)