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consider the molecule ne₂. part: 0 / 2 part 1 of 2 draw the mo diagram …

Question

consider the molecule ne₂. part: 0 / 2 part 1 of 2 draw the mo diagram for the molecule. be sure your diagram contains all of the electrons in the species, including any core electrons.

Explanation:

Step1: Determine number of electrons

Neon (Ne) has 10 electrons. So, Ne₂ has 20 electrons.

Step2: Fill molecular - orbitals

Start filling the molecular - orbitals in order of increasing energy. The order of filling for homonuclear diatomic molecules is $\sigma_{1s}$, $\sigma_{1s}^*$, $\sigma_{2s}$, $\sigma_{2s}^*$, $\pi_{2p_x}=\pi_{2p_y}$, $\sigma_{2p_z}$, $\pi_{2p_x}^*=\pi_{2p_y}^*$, $\sigma_{2p_z}^*$. Fill these orbitals with 20 electrons following Pauli - exclusion principle and Hund's rule.

However, as this is a drawing task and cannot be directly represented in text, the steps to construct the diagram are described above.

Answer:

A proper MO diagram for Ne₂ should have energy on the y - axis and molecular orbitals labeled on the x - axis. The $\sigma_{1s}$, $\sigma_{1s}^*$, $\sigma_{2s}$, $\sigma_{2s}^*$, $\pi_{2p_x}=\pi_{2p_y}$, $\sigma_{2p_z}$, $\pi_{2p_x}^*=\pi_{2p_y}^*$, $\sigma_{2p_z}^*$ orbitals should be drawn with appropriate energy levels. Each orbital can hold a maximum of 2 electrons with opposite spins. The 20 electrons of Ne₂ should be filled in these orbitals starting from the lowest - energy orbital $\sigma_{1s}$.