Question

consider these equations. ch₄(g) → c(s) + 2h₂(g) δh₁ = 74.6kj c(s) + 2cl₂(g) → ccl₄(g) δh₂ = -95.7kj 2h₂(g) + 2cl₂(g) → 4hcl(g) δh₃ = -184.6kj ch₄(g) + 4cl₂(g) → ccl₄(g) + 4hcl(g) δh₄ = -205.7kj complete this based on the diagram. arrow a:

Explanation:

Step1: Analyze the first equation

The first equation $\mathrm{CH}_4(\mathrm{g})\to\mathrm{C}(\mathrm{s}) + 2\mathrm{H}_2(\mathrm{g})\ \Delta H_1 = 74.6\mathrm{kJ}$ represents the decomposition of methane into carbon and hydrogen. The positive $\Delta H$ value indicates an endothermic reaction. Arrow A in the diagram likely corresponds to this endothermic process.

Answer:

74.6 kJ