Question

consider these intermediate chemical equations.
2p(s) + 3cl₂(g) → 2pcl₃(l)
pcl₃(l) + cl₂(g) → pcl₅(s)
when you combine the intermediate chemical equations, which substance do you cancel out?
pcl₅
p
pcl₃
cl₂

Explanation:

Step1: Analyze reactants and products.

The first equation is \(2P(s)+3Cl_2(g)
ightarrow2PCl_3(l)\) and the second is \(PCl_3(l)+Cl_2(g)
ightarrow PCl_5(s)\).

Step2: Identify common substance.

\(PCl_3\) appears as a product in the first - equation and as a reactant in the second equation.

Answer:

\(PCl_3\)