Question

is this the correct change in ph? hint: the change in ph can be negative.
hcl (drops) tube 1 water (ph) tube 2 buffer (ph) tube 3 cytosol (ph)
0 7 9 7
1 3 9 7
3 2 9 7
5 2 9 7
change in ph = final ph - initial ph

Explanation:

Step1: Calculate change in pH for Tube 1

For 0 drops of HCl, initial pH = 7. For 1 drop of HCl, final pH = 3. Change in pH = 3 - 7=-4. For 3 drops, final pH = 2, change in pH = 2 - 7=-5. For 5 drops, final pH = 2, change in pH = 2 - 7=-5.

Step2: Calculate change in pH for Tube 2

Initial pH = 9. For all amounts of HCl drops (0, 1, 3, 5), final pH = 9. Change in pH = 9 - 9 = 0.

Step3: Calculate change in pH for Tube 3

Initial pH = 7. For all amounts of HCl drops (0, 1, 3, 5), final pH = 7. Change in pH = 7 - 7 = 0.

Answer:

Tube 1: -4 (for 1 drop), -5 (for 3 and 5 drops); Tube 2: 0; Tube 3: 0