Question

current attempt in progress
we can describe the combustion of glucose, and the accompanying energy change, as.
$ce{c6h12o6 + 6 o2 -> 6 h2o + 6 co2}$, $delta u$=-5670 kj
the molar energy change, expressed in terms of oxygen consumed, is
○ 945 kj mol⁻¹.
○ 5670 kj mol⁻¹.
○ -945 kj mol⁻¹.
○ -5670 kj mol⁻¹.
○ 472 kj mol⁻¹.

Explanation:

Step1: Identify moles of O₂

From the reaction \( \ce{C6H12O6 + 6 O2 -> 6 H2O + 6 CO2} \), moles of \( \ce{O2} \) is 6.

Step2: Calculate molar energy change for O₂

Given \( \Delta U = -5670 \, \text{kJ} \) for 6 moles of \( \ce{O2} \). Divide \( \Delta U \) by moles of \( \ce{O2} \):
\( \frac{-5670 \, \text{kJ}}{6 \, \text{mol}} = -945 \, \text{kJ mol}^{-1} \).

Answer:

-945 kJ mol⁻¹ (corresponding to the option: -945 kJ mol⁻¹)