Question

data table 2: mass and volume data for unknown samples
a chemistry student uses water displacement to determine the volume of the following samples.
sample mass initial volume final volume volume of sample
1 50.25 g 50.11 ml 60.31 ml
2 63.56 g 49.80 ml 62.50 ml
3 57.65 g 50.22 ml 61.55 ml
4 55.35 g 45.66 ml 56.77 ml
5 74.92 g 50.33 ml 65.33 ml
6 67.78 g 47.55 ml 60.80 ml

1. calculate the volume of the sample and record in the table.

41.calculate density for each sample. please show work below.
42.calculate the average density: show your work

Explanation:

Step1: Calculate volume of each sample

The volume of the sample is found by subtracting the initial volume from the final volume.
For sample 1: $V_1=60.31 - 50.11=10.20$ mL
For sample 2: $V_2=62.50 - 49.80 = 12.70$ mL
For sample 3: $V_3=61.55 - 50.22=11.33$ mL
For sample 4: $V_4=56.77 - 45.66 = 11.11$ mL
For sample 5: $V_5=65.33 - 50.33=15.00$ mL
For sample 6: $V_6=60.80 - 47.55 = 13.25$ mL

Step2: Calculate density of each sample

The density formula is $
ho=\frac{m}{V}$, where $m$ is mass and $V$ is volume.
For sample 1: $
ho_1=\frac{50.25}{10.20}\approx4.93$ g/mL
For sample 2: $
ho_2=\frac{63.56}{12.70}\approx5.00$ g/mL
For sample 3: $
ho_3=\frac{57.65}{11.33}\approx5.09$ g/mL
For sample 4: $
ho_4=\frac{55.35}{11.11}\approx4.98$ g/mL
For sample 5: $
ho_5=\frac{74.92}{15.00}\approx4.99$ g/mL
For sample 6: $
ho_6=\frac{67.78}{13.25}\approx5.12$ g/mL

Step3: Calculate average density

The average density $\bar{
ho}=\frac{
ho_1+
ho_2+
ho_3+
ho_4+
ho_5+
ho_6}{6}$
$\bar{
ho}=\frac{4.93 + 5.00+5.09+4.98+4.99+5.12}{6}=\frac{30.11}{6}\approx5.02$ g/mL

Answer:

Sample	Volume of sample (mL)	Density (g/mL)
2	12.70	5.00
3	11.33	5.09
4	11.11	4.98
5	15.00	4.99
6	13.25	5.12

Average density: 5.02 g/mL