Question

day 5 (10/9)

1. write the name for se₃cl₉
2. write the chemical formula for potassium sulfate.
3. write the chemical formula lead (i) phosphate.

Explanation:

Step1: Name $Se_3Cl_9$

It is a binary covalent compound. Selenium ($Se$) is the first - named element and there are 3 of it, so it's triselenium. Chlorine ($Cl$) is the second - named element, and there are 9 of it, so it's nonachloride. The name is triselenium nonachloride.

Step2: Write formula for potassium sulfate

Potassium has a charge of $K^+$ and sulfate has a charge of $SO_4^{2 - }$. To balance the charges, we need 2 potassium ions for every 1 sulfate ion. The formula is $K_2SO_4$.

Step3: Write formula for lead (I) phosphate

Lead (I) has a charge of $Pb^+$ and phosphate has a charge of $PO_4^{3 - }$. To balance the charges, we need 3 lead (I) ions for every 1 phosphate ion. The formula is $Pb_3PO_4$.

Answer:

1. triselenium nonachloride
2. $K_2SO_4$
3. $Pb_3PO_4$