Question

the density of liquid gold (au) is 19.3 g/cm³. if given a mass of 29.2 kg of this liquid, what is its volume in l? 1.51 l 1.26 l 1260 l 0.631 l

Explanation:

Step1: Convert mass to grams

Since 1 kg = 1000 g, for a mass of 29.2 kg, the mass in grams is $m = 29.2\times1000=29200$ g.

Step2: Use density - mass - volume formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass and $V$ is volume. Rearranging for volume gives $V = \frac{m}{
ho}$. Given $
ho = 19.3$ g/cm³ and $m = 29200$ g, then $V=\frac{29200}{19.3}\text{ cm}^3=1512.95\text{ cm}^3$.

Step3: Convert volume from cm³ to L

Since 1 L = 1000 cm³, then $V=\frac{1512.95}{1000}=1.51295\approx1.51$ L.

Answer:

1.51 L