Question

determine the balanced equation for the neutralization reaction between h₂so₃ and lioh in aqueous solution. phases are optional. balanced chemical equation:

Explanation:

Step1: Write un - balanced reaction

$H_2SO_3 + LiOH
ightarrow Li_2SO_3 + H_2O$

Step2: Balance Li atoms

There are 2 Li atoms in $Li_2SO_3$. So, we need 2 moles of LiOH on the left - hand side.
$H_2SO_3+2LiOH
ightarrow Li_2SO_3 + H_2O$

Step3: Balance H and O atoms

On the left - hand side, we have 4 H atoms ($2$ from $H_2SO_3$ and $2$ from $2LiOH$) and 5 O atoms ($3$ from $H_2SO_3$ and $2$ from $2LiOH$). On the right - hand side, in $Li_2SO_3$ we have 3 O atoms and in $H_2O$ we have 1 O and 2 H atoms. To balance H and O, we need 2 moles of $H_2O$.
$H_2SO_3 + 2LiOH=Li_2SO_3+2H_2O$

Answer:

$H_2SO_3 + 2LiOH=Li_2SO_3+2H_2O$