Question

determine the formulas for these ionic compounds.
copper(i) bromide:
copper(i) oxide:
copper(ii) bromide:
copper(ii) oxide:
iron(iii) bromide:
iron(iii) oxide:
lead(iv) bromide:
lead(iv) oxide:

Explanation:

copper(I) bromide:

Step1: Identify ions

Copper(I) ion: $Cu^+$, Bromide ion: $Br^-$.

Step2: Balance charges

Charge of $Cu^+$ is +1, charge of $Br^-$ is -1. To balance, 1 $Cu^+$ and 1 $Br^-$.

Step1: Identify ions

Copper(I) ion: $Cu^+$, Oxide ion: $O^{2-}$.

Step2: Balance charges

Let number of $Cu^+$ be $x$, $O^{2-}$ be $y$. $x(+1) + y(-2) = 0$. Solve: $x = 2$, $y = 1$.

Step1: Identify ions

Copper(II) ion: $Cu^{2+}$, Bromide ion: $Br^-$.

Step2: Balance charges

Charge of $Cu^{2+}$ is +2, $Br^-$ is -1. So 1 $Cu^{2+}$ and 2 $Br^-$.

Answer:

$CuBr$

copper(I) oxide: