Question

determine the number of particles in the 2.56 mol sample of no2. 1 mol no2 = 6.02×10^23 particles no2 2.56 mol no2 = ?×10^? particles no2 enter the coefficient in the green box and the exponent in the yellow box. round the coefficient to two decimal places.

Explanation:

Step1: Use Avogadro's number ratio

We know that 1 mol of any substance contains $6.02\times 10^{23}$ particles. For 2.56 mol of $NO_2$, we set up a proportion. The number of particles $N$ in 2.56 mol of $NO_2$ is given by $N = 2.56\times(6.02\times 10^{23})$.

Step2: Calculate the result

$N=2.56\times6.02\times 10^{23}=(2.56\times6.02)\times10^{23}=15.4112\times 10^{23}$. In scientific - notation, we rewrite it as $1.54112\times 10^{24}$. Rounding the coefficient to two decimal places, we get $1.54\times 10^{24}$.

Answer:

Coefficient: 1.54, Exponent: 24