Question

determine the volume in ml of a 0.250 m solution of hydrochloric acid needed to make 250.0 ml of a 0.0200 m hydrochloric acid solution. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall dilution formula

The dilution formula is \( M_1V_1 = M_2V_2 \), where \( M_1 \) is the initial molarity, \( V_1 \) is the initial volume, \( M_2 \) is the final molarity, and \( V_2 \) is the final volume. We need to find \( V_1 \).

Step2: Rearrange formula for \( V_1 \)

Rearranging the formula gives \( V_1=\frac{M_2V_2}{M_1} \).

Step3: Substitute values

Given \( M_1 = 0.250\ M \), \( M_2 = 0.0200\ M \), and \( V_2 = 250.0\ mL \). Substituting these values: \( V_1=\frac{0.0200\ M\times250.0\ mL}{0.250\ M} \).

Step4: Calculate the value

First, calculate the numerator: \( 0.0200\times250.0 = 5.00 \). Then divide by the denominator: \( \frac{5.00}{0.250}=20.0 \).

Answer:

20.0