Question

determine the vsepr shape of the given structure. options: hexahedral, square pyramidal, octahedral, square planar

Explanation:

Step1: Analyze the central atom's bonding

The structure has a central S atom bonded to 6 F atoms. First, we determine the electron - pair geometry and molecular geometry using VSEPR theory. The central S atom has 6 bonding pairs (since it is bonded to 6 F atoms) and no lone pairs.

Step2: Recall VSEPR geometries

For a central atom with 6 bonding pairs and 0 lone pairs, the electron - pair geometry and molecular geometry is octahedral. The octahedral geometry has six atoms (or groups) symmetrically arranged around the central atom, with bond angles of approximately 90° between adjacent atoms. Hexahedral is not a standard VSEPR geometry term. Square pyramidal has 5 bonding pairs and 1 lone pair, and square planar has 4 bonding pairs and 2 lone pairs. So, based on the number of bonding pairs (6) around the central S atom, the VSEPR shape is octahedral.

Answer:

Octahedral (the option with the label "Octahedral")