6. diagram the electron distribution of each of the following atoms and write next to the drawing which atom(s) is (are) reactive and which atom(s) is (are) inert and nonreactive. ₂he, ₁₀ne, ₁₁na, and ₁₇cl ₂he ₁₀ne ₁₁na ₁₇cl

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### Step-by-Step Explanation for Electron Distribution and Reactivity Analysis

#### 1. Electron Distribution Basics
Electrons fill energy levels (shells) around the nucleus. The first shell ($n=1$) holds a maximum of 2 electrons, the second shell ($n=2$) holds up to 8, the third shell ($n=3$) holds up to 8 (for elements up to atomic number 20), etc. The formula for the maximum number of electrons in shell $n$ is $2n^2$.

#### 2. Analyzing $_{2}\text{He}$ (Helium)
- **Atomic Number (Z):** 2 (2 protons, 2 electrons).
- **Electron Distribution:**
  - First shell ($n=1$): $2$ electrons (fills the first shell, $2(1)^2 = 2$).
- **Reactivity:** Inert (noble gas). Helium has a full valence shell (2 electrons in the first shell, which is stable for $n=1$).

#### 3. Analyzing $_{10}\text{Ne}$ (Neon)
- **Atomic Number (Z):** 10 (10 protons, 10 electrons).
- **Electron Distribution:**
  - First shell ($n=1$): $2$ electrons (filled, $2(1)^2 = 2$).
  - Second shell ($n=2$): $8$ electrons (filled, $2(2)^2 = 8$).
- **Reactivity:** Inert (noble gas). Neon has a full valence shell (8 electrons in the second shell, stable).

#### 4. Analyzing $_{11}\text{Na}$ (Sodium)
- **Atomic Number (Z):** 11 (11 protons, 11 electrons).
- **Electron Distribution:**
  - First shell ($n=1$): $2$ electrons (filled).
  - Second shell ($n=2$): $8$ electrons (filled).
  - Third shell ($n=3$): $1$ electron (valence shell has 1 electron).
- **Reactivity:** Reactive. Sodium has 1 valence electron, which it tends to lose to achieve a stable octet (like Ne’s electron configuration).

#### 5. Analyzing $_{17}\text{Cl}$ (Chlorine)
- **Atomic Number (Z):** 17 (17 protons, 17 electrons).
- **Electron Distribution:**
  - First shell ($n=1$): $2$ electrons (filled).
  - Second shell ($n=2$): $8$ electrons (filled).
  - Third shell ($n=3$): $7$ electrons (valence shell has 7 electrons).
- **Reactivity:** Reactive. Chlorine has 7 valence electrons, so it tends to gain 1 electron to achieve a stable octet (like Ar’s electron configuration).

### Summary of Electron Distributions and Reactivity
| Atom       | Electron Distribution (Shells: $n=1, n=2, n=3$) | Reactivity       |
|------------|---------------------------------------------------|------------------|
| $_{2}\text{He}$ | $2$ (only $n=1$)                               | Inert (nonreactive) |
| $_{10}\text{Ne}$ | $2, 8$ ( $n=1, n=2$)                          | Inert (nonreactive) |
| $_{11}\text{Na}$ | $2, 8, 1$ ( $n=1, n=2, n=3$)                  | Reactive         |
| $_{17}\text{Cl}$ | $2, 8, 7$ ( $n=1, n=2, n=3$)                  | Reactive         |

### Drawing the Electron Distributions (Bohr Models)
- **Helium ($_{2}\text{He}$):**
  - Nucleus (label “He” or “2p, 2n”) at the center.
  - 1st shell: 2 electrons (draw as dots or circles around the nucleus).

- **Neon ($_{10}\text{Ne}$):**
  - Nucleus (label “Ne” or “10p, 10n”) at the center.
  - 1st shell: 2 electrons.
  - 2nd shell: 8 electrons (draw around the 1st shell).

- **Sodium ($_{11}\text{Na}$):**
  - Nucleus (label “Na” or “11p, 12n”) at the center.
  - 1st shell: 2 electrons.
  - 2nd shell: 8 electrons.
  - 3rd shell: 1 electron (draw around the 2nd shell).

- **Chlorine ($_{17}\text{Cl}$):**
  - Nucleus (label “Cl” or “17p, 18n”) at the center.
  - 1st shell: 2 electrons.
  - 2nd shell: 8 electrons.
  - 3rd shell: 7 electrons (draw around the 2nd shell).

### Final Answer (Reactivity Summary)
- **Inert (nonreactive) atoms:** $_{2}\text{He}$, $_{10}\text{Ne}$ (full valence shells).
- **Reactive atoms:** $_{11}\text{Na}$ (loses 1 electron), $_{17}\text{Cl}$ (gains 1 electron).

For the electron distribution diagrams, follow the shell - filling rules and draw the shells with the correct number of electrons as explained.

Atom	Electron Distribution (Shells: \(n=1, n=2, n=3\))	Reactivity
\(_{10}\text{Ne}\)	\(2, 8\) ( \(n=1, n=2\))	Inert (nonreactive)
\(_{11}\text{Na}\)	\(2, 8, 1\) ( \(n=1, n=2, n=3\))	Reactive
\(_{17}\text{Cl}\)	\(2, 8, 7\) ( \(n=1, n=2, n=3\))	Reactive

Atom	Electron Distribution (Shells: \(n=1, n=2, n=3\))	Reactivity
\(_{10}\text{Ne}\)	\(2, 8\) ( \(n=1, n=2\))	Inert (nonreactive)
\(_{11}\text{Na}\)	\(2, 8, 1\) ( \(n=1, n=2, n=3\))	Reactive
\(_{17}\text{Cl}\)	\(2, 8, 7\) ( \(n=1, n=2, n=3\))	Reactive

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QUESTION IMAGE

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Explanation:

Step-by-Step Explanation for Electron Distribution and Reactivity Analysis

1. Electron Distribution Basics

2. Analyzing \(_{2}\text{He}\) (Helium)

3. Analyzing \(_{10}\text{Ne}\) (Neon)

4. Analyzing \(_{11}\text{Na}\) (Sodium)

5. Analyzing \(_{17}\text{Cl}\) (Chlorine)

Summary of Electron Distributions and Reactivity

Drawing the Electron Distributions (Bohr Models)

Final Answer (Reactivity Summary)

Answer: