Question

the double - replacement reaction is between aqueous lead(ii) nitrate and potassium iodide: pb(no3)2 + ki →? identify the possible products of this reaction. select all that apply: pbk, (no3)2i, pbi, kno3, k(no3)2, pbi2. i need a hint. 0 / 4 submissions used. score: 0 / 1. heads up. you need to submit this answer for it to save and be graded.

Explanation:

Step1: Recall double - replacement reaction rule

In a double - replacement reaction of the form \(AB + CD
ightarrow AD+CB\), for the reaction \(Pb(NO_3)_2+KI
ightarrow\), the cations (\(Pb^{2 +}\) and \(K^+\)) and anions (\(NO_3^-\) and \(I^-\)) will exchange partners.

Step2: Determine the products

When \(Pb^{2+}\) combines with \(I^-\), it forms \(PbI_2\) (since the charge of \(Pb\) is \( + 2\) and charge of \(I\) is \(-1\), so we need 2 \(I^-\) ions to balance the charge). When \(K^+\) combines with \(NO_3^-\), it forms \(KNO_3\).

Answer:

\(KNO_3\), \(PbI_2\)