Question

drag each label to the correct location on the image.
label each half cell in this diagram of a voltaic cell to identify which electrode it contains and the process occurring at the electrode.

anode cathode reduction oxidation

e⁻ → e⁻ →

zn⁻ cu⁺

salt bridge

electrode electrode

zn²⁺ cu²⁺

process process

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Explanation:

1. For the left half - cell (with Zn electrode):

• In a voltaic cell, the anode is where oxidation occurs. The Zn electrode is losing electrons (as seen from the formation of \(Zn^{2 +}\) and the direction of electron flow, electrons are leaving the Zn electrode). So the left electrode is the anode, and the process is oxidation. The reaction at the Zn anode is \(Zn(s)

ightarrow Zn^{2+}(aq)+2e^-\), which is an oxidation reaction (loss of electrons).

1. For the right half - cell (with Cu electrode):

• The cathode is where reduction occurs. The Cu electrode is gaining electrons (electrons are flowing towards the Cu electrode). The \(Cu^{2+}\) ions in the solution are being reduced to Cu metal (\(Cu^{2+}(aq)+2e^-

ightarrow Cu(s)\)). So the right electrode is the cathode, and the process is reduction.

Answer:

• Left electrode (Zn electrode): anode; Left process: oxidation
• Right electrode (Cu electrode): cathode; Right process: reduction

So the labels should be:

• Left electrode box: anode
• Left process box: oxidation
• Right electrode box: cathode
• Right process box: reduction