Question

drag the tiles to the correct boxes. not all tiles will be used. the oxidation number of oxygen is -2, and that of chlorine is -1. use this information to match the names of the compounds to their chemical formulas. manganese(ii) chloride manganese(iv) chloride manganese(ii) oxide manganese(iv) oxide mncl₂ → mno₂ → reset next

Explanation:

To solve this, we use the oxidation numbers to determine the correct compound names for the given formulas.

For $\boldsymbol{MnCl_2}$:

• Chlorine (Cl) has an oxidation number of -1. Let the oxidation number of Mn be $x$.
• In a compound, the sum of oxidation numbers is zero. So, for $MnCl_2$: $x + 2\times(-1) = 0$.
• Solving: $x - 2 = 0 \implies x = +2$.
• So, Mn has an oxidation state of +2, and the anion is chloride (Cl⁻). Thus, the compound is manganese(II) chloride.

For $\boldsymbol{MnO_2}$:

• Oxygen (O) has an oxidation number of -2. Let the oxidation number of Mn be $y$.
• For $MnO_2$: $y + 2\times(-2) = 0$.
• Solving: $y - 4 = 0 \implies y = +4$.
• So, Mn has an oxidation state of +4, and the anion is oxide (O²⁻). Thus, the compound is manganese(IV) oxide.

Final Matching:

• $MnCl_2$: manganese(II) chloride
• $MnO_2$: manganese(IV) oxide

So, drag "manganese(II) chloride" to the box next to $MnCl_2$ and "manganese(IV) oxide" to the box next to $MnO_2$.

Answer:

To solve this, we use the oxidation numbers to determine the correct compound names for the given formulas.

For $\boldsymbol{MnCl_2}$:

• Chlorine (Cl) has an oxidation number of -1. Let the oxidation number of Mn be $x$.
• In a compound, the sum of oxidation numbers is zero. So, for $MnCl_2$: $x + 2\times(-1) = 0$.
• Solving: $x - 2 = 0 \implies x = +2$.
• So, Mn has an oxidation state of +2, and the anion is chloride (Cl⁻). Thus, the compound is manganese(II) chloride.

For $\boldsymbol{MnO_2}$:

• Oxygen (O) has an oxidation number of -2. Let the oxidation number of Mn be $y$.
• For $MnO_2$: $y + 2\times(-2) = 0$.
• Solving: $y - 4 = 0 \implies y = +4$.
• So, Mn has an oxidation state of +4, and the anion is oxide (O²⁻). Thus, the compound is manganese(IV) oxide.

Final Matching:

• $MnCl_2$: manganese(II) chloride
• $MnO_2$: manganese(IV) oxide

So, drag "manganese(II) chloride" to the box next to $MnCl_2$ and "manganese(IV) oxide" to the box next to $MnO_2$.