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2. draw the lewis dot structure for oxygen (o₂)

Question

  1. draw the lewis dot structure for oxygen (o₂)

Explanation:

Step1: Determine valence electrons

Oxygen has 6 valence electrons per atom, so $O_2$ has 12 in total.

Step2: Arrange atoms and share electrons

Place two O atoms adjacent. Share 4 electrons (double - bond) to satisfy octet rule.

Step3: Add lone pairs

Each O has 2 lone pairs.

Answer:

:O::O: (with 2 lone - pairs on each O)