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for each of the atoms/ions below, write the full electron configuration…

Question

for each of the atoms/ions below, write the full electron configuration. 1. *neutral atom of iron 2. bromine ion with a charge of - 1 for each of the atoms/ions below, write the abbreviated notation. 3. *neutral atom of tellurium (te) 4. neutral atom of calcium for each of the atoms/ions below, write the orbital notation. 5. **sulfur ion with a charge of - 2 6. calcium ion with a charge of +2

Explanation:

Step1: Recall electron - filling rules

Use the Aufbau principle, Pauli - exclusion principle, and Hund's rule to fill electrons into orbitals.

Step2: Determine atomic numbers

  • Iron (Fe) has an atomic number of 26.
  • Bromine (Br) has an atomic number of 35, and the Br⁻ ion has 36 electrons.
  • Tellurium (Te) has an atomic number of 52.
  • Calcium (Ca) has an atomic number of 20, and the Ca²⁺ ion has 18 electrons.
  • Sulfur (S) has an atomic number of 16, and the S²⁻ ion has 18 electrons.

Step3: Write full electron configurations

1. Neutral atom of iron (Fe)

1s²2s²2p⁶3s²3p⁶4s²3d⁶

2. Bromine ion with a charge of - 1 (Br⁻)

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶

Step4: Write abbreviated notations

3. Neutral atom of tellurium (Te)

[Kr]4d¹⁰5s²5p⁴

4. Neutral atom of calcium (Ca)

[Ar]4s²

Step5: Write orbital notations

5. Sulfur ion with a charge of - 2 (S²⁻)

1s: ↑↓
2s: ↑↓
2p: ↑↓ ↑↓ ↑↓
3s: ↑↓
3p: ↑↓ ↑↓ ↑↓

6. Calcium ion with a charge of + 2 (Ca²⁺)

1s: ↑↓
2s: ↑↓
2p: ↑↓ ↑↓ ↑↓
3s: ↑↓
3p: ↑↓ ↑↓ ↑↓

Answer:

  1. 1s²2s²2p⁶3s²3p⁶4s²3d⁶
  2. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶
  3. [Kr]4d¹⁰5s²5p⁴
  4. [Ar]4s²
  5. 1s: ↑↓; 2s: ↑↓; 2p: ↑↓ ↑↓ ↑↓; 3s: ↑↓; 3p: ↑↓ ↑↓ ↑↓
  6. 1s: ↑↓; 2s: ↑↓; 2p: ↑↓ ↑↓ ↑↓; 3s: ↑↓; 3p: ↑↓ ↑↓ ↑↓