QUESTION IMAGE
Question
for every 1 molecule of glucose (c₆h₁₂o₆) and 6 molecules of oxygen gas (o₂) that go into cellular respiration, the process produces 6 molecules of carbon dioxide gas (co₂) and 6 molecules of water (h₂o). complete the table.
type of atom,number of atoms in 6 molecules of carbon dioxide,number of atoms in 6 molecules of water,total number of atoms in products
h,0,,
c,6,0,
o,,6,
work it out
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how are substances represented by chemical,identify reactants and products
Step1: Calculate number of H atoms in 6 water molecules
Each water ($H_2O$) molecule has 2 H - atoms. So for 6 water molecules, the number of H - atoms is $2\times6 = 12$.
Step2: Calculate total number of H atoms in products
Since there are 0 H - atoms in 6 $CO_2$ molecules and 12 H - atoms in 6 $H_2O$ molecules, the total number of H - atoms in products is 12.
Step3: Calculate number of O atoms in 6 carbon - dioxide molecules
Each carbon - dioxide ($CO_2$) molecule has 2 O - atoms. So for 6 $CO_2$ molecules, the number of O - atoms is $2\times6=12$.
Step4: Calculate total number of O atoms in products
There are 12 O - atoms in 6 $CO_2$ molecules and 6 O - atoms in 6 $H_2O$ molecules. So the total number of O - atoms in products is $12 + 6=18$.
Step5: Calculate total number of C atoms in products
There are 6 C - atoms in 6 $CO_2$ molecules and 0 C - atoms in 6 $H_2O$ molecules. So the total number of C - atoms in products is 6.
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| Type of atom | Number of atoms in 6 molecules of carbon dioxide | Number of atoms in 6 molecules of water | Total number of atoms in products |
|---|---|---|---|
| C | 6 | 0 | 6 |
| O | 12 | 6 | 18 |