Question

exercise 3.31 - enhanced - with expanded hints
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pcl₃ ch₄ srf₂ fe₂o₃
molecular ionic

Explanation:

Step1: Recall bonding rules

Molecular compounds form between non - metals. Ionic compounds form between a metal and a non - metal.

Step2: Analyze $\text{PCl}_3$

P (phosphorus) and Cl (chlorine) are non - metals. So, $\text{PCl}_3$ is molecular.

Step3: Analyze $\text{CH}_4$

C (carbon) and H (hydrogen) are non - metals. So, $\text{CH}_4$ is molecular.

Step4: Analyze $\text{SrF}_2$

Sr (strontium) is a metal and F (fluorine) is a non - metal. So, $\text{SrF}_2$ is ionic.

Step5: Analyze $\text{Fe}_2\text{O}_3$

Fe (iron) is a metal and O (oxygen) is a non - metal. So, $\text{Fe}_2\text{O}_3$ is ionic.

Answer:

Molecular: $\text{PCl}_3$, $\text{CH}_4$
Ionic: $\text{SrF}_2$, $\text{Fe}_2\text{O}_3$