QUESTION IMAGE
Question
factor each trinomial.
- $6c^2 + 11c + 4$
- $4x^2 + 2x - 12$
- $x^2 - 8x + 15$
- $x^2 - 3x - 40$
- $2m^2 + m - 28$
- $x^2 - 18x + 81$
- $9x^2 + 48x + 64$
Response
Problem 1: Factor \(6c^2 + 11c + 4\)
Step1: Find two numbers that multiply to \(6\times4 = 24\) and add to \(11\). The numbers are \(8\) and \(3\).
Rewrite the middle term: \(6c^2 + 8c + 3c + 4\)
Step2: Group the terms.
\((6c^2 + 8c) + (3c + 4)\)
Step3: Factor out the GCF from each group.
\(2c(3c + 4) + 1(3c + 4)\)
Step4: Factor out the common binomial factor.
\((2c + 1)(3c + 4)\)
Step1: Factor out the GCF of \(2\) from all terms.
\(2(2x^2 + x - 6)\)
Step2: Factor the quadratic inside the parentheses. Find two numbers that multiply to \(2\times(-6)= -12\) and add to \(1\). The numbers are \(4\) and \(-3\).
Rewrite the middle term: \(2(2x^2 + 4x - 3x - 6)\)
Step3: Group the terms.
\(2[(2x^2 + 4x) + (-3x - 6)]\)
Step4: Factor out the GCF from each group.
\(2[2x(x + 2) - 3(x + 2)]\)
Step5: Factor out the common binomial factor.
\(2(2x - 3)(x + 2)\)
Step1: Find two numbers that multiply to \(15\) and add to \(-8\). The numbers are \(-5\) and \(-3\).
Step2: Write the factored form.
\((x - 5)(x - 3)\)
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\((2c + 1)(3c + 4)\)