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factor each trinomial. 1. $6c^2 + 11c + 4$ 2. $4x^2 + 2x - 12$ 3. $x^2 …

Question

factor each trinomial.

  1. $6c^2 + 11c + 4$
  2. $4x^2 + 2x - 12$
  3. $x^2 - 8x + 15$
  4. $x^2 - 3x - 40$
  5. $2m^2 + m - 28$
  6. $x^2 - 18x + 81$
  7. $9x^2 + 48x + 64$

Explanation:

Response
Problem 1: Factor \(6c^2 + 11c + 4\)

Step1: Find two numbers that multiply to \(6\times4 = 24\) and add to \(11\). The numbers are \(8\) and \(3\).

Rewrite the middle term: \(6c^2 + 8c + 3c + 4\)

Step2: Group the terms.

\((6c^2 + 8c) + (3c + 4)\)

Step3: Factor out the GCF from each group.

\(2c(3c + 4) + 1(3c + 4)\)

Step4: Factor out the common binomial factor.

\((2c + 1)(3c + 4)\)

Step1: Factor out the GCF of \(2\) from all terms.

\(2(2x^2 + x - 6)\)

Step2: Factor the quadratic inside the parentheses. Find two numbers that multiply to \(2\times(-6)= -12\) and add to \(1\). The numbers are \(4\) and \(-3\).

Rewrite the middle term: \(2(2x^2 + 4x - 3x - 6)\)

Step3: Group the terms.

\(2[(2x^2 + 4x) + (-3x - 6)]\)

Step4: Factor out the GCF from each group.

\(2[2x(x + 2) - 3(x + 2)]\)

Step5: Factor out the common binomial factor.

\(2(2x - 3)(x + 2)\)

Step1: Find two numbers that multiply to \(15\) and add to \(-8\). The numbers are \(-5\) and \(-3\).

Step2: Write the factored form.

\((x - 5)(x - 3)\)

Answer:

\((2c + 1)(3c + 4)\)

Problem 2: Factor \(4x^2 + 2x - 12\)