Question

1. fill in the following table. be careful, it contains atoms, ions and isotopes. atomic # mass # # of protons # of electrons # of neutrons net charge cation / anion 13 13 15 ag1+ 46 30 35 0 55 133 3+ p3-

Explanation:

Step1: Recall atomic number = # of protons

For the first row, given atomic number 13, the number of protons is 13. The number of electrons is 13, and the number of neutrons is 15. Mass number = # of protons+# of neutrons = 13 + 15=28. Net charge = # of protons - # of electrons. Here, net charge = 13 - 13 = 0. Since net - charge is 0, it is a neutral atom.

Step2: For silver ion ($Ag^{1 +}$)

The number of electrons is 46. For a cation with a + 1 charge, # of protons= # of electrons+1. So, # of protons = 46 + 1=47. Atomic number of silver is 47. Mass number of a common silver isotope is 108 (but not given directly here, we focus on the known values). Net charge is + 1, so it is a cation.

Step3: Given # of protons = 30

Atomic number = 30 (zinc). Mass number = # of protons+# of neutrons = 30+35 = 65. Since net charge is 0, # of electrons = # of protons = 30. It is a neutral atom.

Step4: Given atomic number 55 (cesium) and mass number 133

of protons = 55. Net charge is 3 +, so # of electrons= # of protons - 3=55 - 3 = 52. # of neutrons=Mass number - # of protons = 133 - 55 = 78. It is a cation.

Step5: For the last row (assuming it is $P^{3 -}$)

Phosphorus has atomic number 15. So, # of protons = 15. For an anion with a - 3 charge, # of electrons= # of protons+3 = 15+3 = 18. Mass number of a common phosphorus isotope is 31, so # of neutrons=31 - 15 = 16. Net charge is - 3, so it is an anion.

Symbol	Atomic #	Mass #	# of Protons	# of Electrons	# of Neutrons	Net Charge	Cation/Anion
$Ag^{1+}$	47	-	47	46	-	+ 1	Cation
Zn	30	65	30	30	35	0	Atom
$Cs^{3+}$	55	133	55	52	78	+ 3	Cation
$P^{3 -}$	15	31	15	18	16	- 3	Anion

Answer:

Symbol	Atomic #	Mass #	# of Protons	# of Electrons	# of Neutrons	Net Charge	Cation/Anion
$Ag^{1+}$	47	-	47	46	-	+ 1	Cation
Zn	30	65	30	30	35	0	Atom
$Cs^{3+}$	55	133	55	52	78	+ 3	Cation
$P^{3 -}$	15	31	15	18	16	- 3	Anion