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QUESTION IMAGE

fill in the missing information! | symbol | atom or ion? check all that…

Question

fill in the missing information!

| symbol | atom or ion?
check all that apply | number of
protons | number of
electrons |

$\text{b}^{2+}$$square$ neutral atom $\boldsymbol{checkmark}$ cation $square$ anion$square$$square$
$square$$\boldsymbol{checkmark}$ neutral atom $square$ cation $square$ anion$square$12
$square$$square$ neutral atom $square$ cation $square$ anion5254

Explanation:

Response
First Row (Symbol: $\text{B}^{2+}$)
Step 1: Determine number of protons

The symbol is B (Boron). The atomic number of Boron is 5, so the number of protons is 5.

Step 2: Determine number of electrons

For a cation $\text{B}^{2+}$, it has lost 2 electrons. A neutral B atom has 5 electrons, so the number of electrons is $5 - 2 = 3$.

Second Row (Neutral atom, electrons = 12)
Step 1: Determine number of protons

In a neutral atom, number of protons = number of electrons. So number of protons is 12. The element with atomic number 12 is Magnesium (Mg), so the symbol is Mg.

Third Row (Protons = 52, Electrons = 54)
Step 1: Determine the ion type

Number of electrons (54) > number of protons (52), so it is an anion.

Step 2: Determine the symbol

The element with atomic number 52 is Tellurium (Te). Since it has gained $54 - 52 = 2$ electrons, the symbol is $\text{Te}^{2-}$.

Filled Table:
symbolatom or ion? <br> check all that applynumber of <br> protonsnumber of <br> electrons
$\text{Mg}$$\boldsymbol{\checkmark}$ neutral atom $\square$ cation $\square$ anion1212
$\text{Te}^{2-}$$\square$ neutral atom $\square$ cation $\boldsymbol{\checkmark}$ anion5254

Answer:

s for each missing cell:

  • First row protons: $\boldsymbol{5}$, electrons: $\boldsymbol{3}$
  • Second row symbol: $\boldsymbol{\text{Mg}}$, protons: $\boldsymbol{12}$
  • Third row symbol: $\boldsymbol{\text{Te}^{2-}}$, ion type: $\boldsymbol{\text{anion}}$ (checked)