QUESTION IMAGE
Question
fill in the missing information!
| symbol | atom or ion?
check all that apply | number of
protons | number of
electrons |
| $\text{b}^{2+}$ | $square$ neutral atom $\boldsymbol{checkmark}$ cation $square$ anion | $square$ | $square$ |
| $square$ | $\boldsymbol{checkmark}$ neutral atom $square$ cation $square$ anion | $square$ | 12 |
| $square$ | $square$ neutral atom $square$ cation $square$ anion | 52 | 54 |
First Row (Symbol: $\text{B}^{2+}$)
Step 1: Determine number of protons
The symbol is B (Boron). The atomic number of Boron is 5, so the number of protons is 5.
Step 2: Determine number of electrons
For a cation $\text{B}^{2+}$, it has lost 2 electrons. A neutral B atom has 5 electrons, so the number of electrons is $5 - 2 = 3$.
Second Row (Neutral atom, electrons = 12)
Step 1: Determine number of protons
In a neutral atom, number of protons = number of electrons. So number of protons is 12. The element with atomic number 12 is Magnesium (Mg), so the symbol is Mg.
Third Row (Protons = 52, Electrons = 54)
Step 1: Determine the ion type
Number of electrons (54) > number of protons (52), so it is an anion.
Step 2: Determine the symbol
The element with atomic number 52 is Tellurium (Te). Since it has gained $54 - 52 = 2$ electrons, the symbol is $\text{Te}^{2-}$.
Filled Table:
| symbol | atom or ion? <br> check all that apply | number of <br> protons | number of <br> electrons |
|---|---|---|---|
| $\text{Mg}$ | $\boldsymbol{\checkmark}$ neutral atom $\square$ cation $\square$ anion | 12 | 12 |
| $\text{Te}^{2-}$ | $\square$ neutral atom $\square$ cation $\boldsymbol{\checkmark}$ anion | 52 | 54 |
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s for each missing cell:
- First row protons: $\boldsymbol{5}$, electrons: $\boldsymbol{3}$
- Second row symbol: $\boldsymbol{\text{Mg}}$, protons: $\boldsymbol{12}$
- Third row symbol: $\boldsymbol{\text{Te}^{2-}}$, ion type: $\boldsymbol{\text{anion}}$ (checked)