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(a) fill in the sample means in the table. do not round your answers. s…

Question

(a) fill in the sample means in the table. do not round your answers. sample backpack weight (in pounds) sample mean 1 6, 7, 9, 3, 6 2 6, 7, 5, 9, 4 3 8, 5, 8, 7, 4 (b) use the table to calculate the range of the sample means. range of sample means: (c) the students are going to use the sample means to estimate the mean backpack weight of their schoolmates. select all the true statements below

Explanation:

Response
Part (a)

Step 1: Calculate sample mean for Sample 1

The formula for the sample mean $\bar{x}$ is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data points and $n$ is the number of data points. For Sample 1, the data points are 6, 7, 9, 3, 6. The sum is $6 + 7+9 + 3+6=31$. There are $n = 5$ data points. So the sample mean is $\frac{31}{5}=6.2$.

Step 2: Calculate sample mean for Sample 2

For Sample 2, the data points are 6, 7, 5, 9, 4. The sum is $6 + 7+5 + 9+4=31$. With $n = 5$, the sample mean is $\frac{31}{5}=6.2$. Wait, no, $6 + 7=13$, $13+5 = 18$, $18+9=27$, $27 + 4=31$? Wait, no, 6+7+5+9+4: 6+7=13, 13+5=18, 18+9=27, 27+4=31? Wait, no, 6+7=13, 13+5=18, 18+9=27, 27+4=31? Wait, no, 6+7+5+9+4 = 31? Wait, 6+7=13, 13+5=18, 18+9=27, 27+4=31. Then $\frac{31}{5}=6.2$? Wait, no, 6+7+5+9+4: 6+7=13, 13+5=18, 18+9=27, 27+4=31. So mean is 31/5 = 6.2? Wait, no, maybe I made a mistake. Wait 6+7+5+9+4: 6+7=13, 13+5=18, 18+9=27, 27+4=31. Yes. Then Sample 2 mean is 31/5 = 6.2? Wait, no, wait Sample 3: 8,5,8,7,4. Sum is 8+5+8+7+4=32. Then mean is 32/5 = 6.4. Wait, let's recalculate Sample 1: 6+7+9+3+6. 6+7=13, 13+9=22, 22+3=25, 25+6=31. So 31/5 = 6.2. Sample 2: 6+7+5+9+4. 6+7=13, 13+5=18, 18+9=27, 27+4=31. 31/5=6.2. Sample 3: 8+5+8+7+4. 8+5=13, 13+8=21, 21+7=28, 28+4=32. 32/5 = 6.4.

Wait, maybe I miscalculated Sample 2. Let's check again: 6,7,5,9,4. 6+7=13, 13+5=18, 18+9=27, 27+4=31. Yes, sum is 31. So mean is 31/5 = 6.2. Sample 3: 8+5+8+7+4. 8+5=13, 13+8=21, 21+7=28, 28+4=32. So mean is 32/5 = 6.4.

So:

Sample 1: sum = 6+7+9+3+6 = 31, mean = 31/5 = 6.2

Sample 2: sum = 6+7+5+9+4 = 31, mean = 31/5 = 6.2

Sample 3: sum = 8+5+8+7+4 = 32, mean = 32/5 = 6.4

Part (b)

Step 1: Identify the maximum and minimum sample means

From part (a), the sample means are 6.2, 6.2, and 6.4. The maximum value is 6.4 and the minimum value is 6.2.

Step 2: Calculate the range

The range is calculated as $Range = \text{Maximum value}-\text{Minimum value}$. So $Range = 6.4 - 6.2 = 0.2$.

Part (a) Answers:

Sample 1 mean: $\boldsymbol{6.2}$

Sample 2 mean: $\boldsymbol{6.2}$

Sample 3 mean: $\boldsymbol{6.4}$

Part (b) Answer:

Range of sample means: $\boldsymbol{0.2}$

(Note: For part (c), since the options are not provided, we can't answer it. If you provide the options, we can help you with that part too.)

Answer:

Step 1: Identify the maximum and minimum sample means

From part (a), the sample means are 6.2, 6.2, and 6.4. The maximum value is 6.4 and the minimum value is 6.2.

Step 2: Calculate the range

The range is calculated as $Range = \text{Maximum value}-\text{Minimum value}$. So $Range = 6.4 - 6.2 = 0.2$.

Part (a) Answers:

Sample 1 mean: $\boldsymbol{6.2}$

Sample 2 mean: $\boldsymbol{6.2}$

Sample 3 mean: $\boldsymbol{6.4}$

Part (b) Answer:

Range of sample means: $\boldsymbol{0.2}$

(Note: For part (c), since the options are not provided, we can't answer it. If you provide the options, we can help you with that part too.)