Question

1. give the electron configuration for sulfur using orbital (box) diagrams. use the noble gas abbreviation method.

Explanation:

Step1: Determine sulfur's atomic number

Sulfur has an atomic number of 16.

Step2: Identify the nearest noble - gas

The nearest noble - gas before sulfur is neon (Ne) with an atomic number of 10.

Step3: Write the noble - gas core

We start with the noble - gas core of neon, which is written as [Ne].

Step4: Determine the remaining electrons

After using the 10 electrons from neon, we have 16 - 10=6 remaining electrons.

Step5: Fill the remaining orbitals

The remaining 6 electrons fill the 3s and 3p orbitals. The 3s orbital gets 2 electrons and the 3p orbitals get 4 electrons. In orbital (box) diagram form, after [Ne], we have a filled 3s orbital (represented as one box with two electrons with opposite spins) and three 3p orbitals with 4 electrons (two in one orbital with opposite spins and one electron each in the other two orbitals with parallel spins). The electron configuration in noble - gas abbreviation and orbital box form is [Ne] $\boxed{\uparrow\downarrow}$ $\boxed{\uparrow\downarrow}$ $\boxed{\uparrow}$ $\boxed{\uparrow}$

Answer:

[Ne] $\boxed{\uparrow\downarrow}$ $\boxed{\uparrow\downarrow}$ $\boxed{\uparrow}$ $\boxed{\uparrow}$