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given 367 g of al2o3, determine the number of moles of al2o3. 1 mol al2…

Question

given 367 g of al2o3, determine the number of moles of al2o3. 1 mol al2o3 = 101.96 g al2o3 ? mol al2o3 = 367 g al2o3

Explanation:

Step1: Identify the formula

Use the formula $n=\frac{m}{M}$, where $n$ is the number of moles, $m$ is the mass, and $M$ is the molar - mass.

Step2: Substitute the values

Given $m = 367\ g$ and $M=101.96\ g/mol$. So $n=\frac{367}{101.96}$.

Step3: Calculate the result

$n=\frac{367}{101.96}\approx3.60\ mol$

Answer:

$3.60$