Question

given the electronegativity of each of the following atoms, rank the bonds from most polar (number 1) to least polar (number 5). o = 3.5 n = 3.0 c = 2.5 h = 2.1 rank the options below. c-o o-h c-h c-n c-c

Explanation:

Step1: Calculate electronegativity differences

For O-H: $|3.5 - 2.1| = 1.4$
For C-O: $|3.5 - 2.5| = 1.0$
For C-N: $|3.0 - 2.5| = 0.5$
For C-H: $|2.5 - 2.1| = 0.4$
For C-C: $|2.5 - 2.5| = 0.0$

Step2: Rank by difference magnitude

Larger difference = more polar. Order from largest to smallest difference.

Answer:

1. O-H
2. C-O
3. C-N
4. C-H
5. C-C