Question

given that the molar mass of nacl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of nacl in 500 ml of solution? use molarity = \frac{moles of solute}{liters of solution} \bigcirc 0.333 m \bigcirc 0.751 m \bigcirc 1.50 m \bigcirc 3.00 m

Explanation:

Step1: Calculate moles of NaCl

Moles = $\frac{\text{mass}}{\text{molar mass}}$ = $\frac{87.75\ \text{g}}{58.44\ \text{g/mol}}$ ≈ 1.50 mol

Step2: Convert volume to liters

500 mL = $\frac{500}{1000}$ L = 0.500 L

Step3: Calculate molarity

Molarity = $\frac{\text{moles of solute}}{\text{liters of solution}}$ = $\frac{1.50\ \text{mol}}{0.500\ \text{L}}$ = 3.00 M

Answer:

3.00 M