QUESTION IMAGE
Question
given this table of electronegativities:
| atom | electronegativity |
|---|---|
| c | 2.6 |
| n | 3.0 |
| o | 3.4 |
| f | 4.0 |
| s | 2.6 |
| br | 3.0 |
| cl | 3.2 |
| p | 2.2 |
| i | 2.7 |
list the following molecules in order of increasing dipole moment: hf, ni₃, co, co₂
Step1: Recall dipole - moment concept
Dipole moment is related to electronegativity difference and molecular geometry. Non - polar molecules have zero dipole moment.
Step2: Analyze $CO_2$
$CO_2$ is a linear molecule with a symmetrical structure. The electronegativity difference between C and O is $3.4 - 2.6=0.8$, but due to its linear geometry ($O = C = O$), the bond dipoles cancel out, so $\mu_{CO_2}=0$.
Step3: Analyze $CO$
For $CO$, the electronegativity difference between C and O is $3.4 - 2.6 = 0.8$. It is a polar molecule with a non - zero dipole moment.
Step4: Analyze $NI_3$
In $NI_3$, the electronegativity difference between N and I is $3.0 - 2.7=0.3$. The molecule has a trigonal pyramidal geometry, so it has a non - zero dipole moment.
Step5: Analyze $HF$
In $HF$, the electronegativity difference between H and F is $4.0 - 2.2 = 1.8$. It is a highly polar molecule with a large dipole moment.
Step6: Compare dipole moments
Based on the above analysis, the order of increasing dipole moment is $CO_2
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$CO_2