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graph the equation shown below by transforming the given graph of the p…

Question

graph the equation shown below by transforming the given graph of the parent function.
$y = (x - 4)^2 + 5$

Explanation:

Step1: Identify the parent function

The parent function of \( y=(x - 4)^{2}+5 \) is \( y = x^{2} \), which is a parabola with vertex at \( (0,0) \), opening upwards.

Step2: Analyze horizontal shift

For a function of the form \( y=(x - h)^{2}+k \), the horizontal shift is determined by \( h \). Here, \( h = 4 \), so we shift the graph of \( y = x^{2} \) 4 units to the right.

Step3: Analyze vertical shift

The vertical shift is determined by \( k \). Here, \( k = 5 \), so we shift the graph (after horizontal shift) 5 units up.

Step4: Determine the new vertex

The vertex of the parent function \( y = x^{2} \) is \( (0,0) \). After shifting 4 units right and 5 units up, the new vertex is \( (4,5) \). The parabola will have the same shape (since the coefficient of \( x^{2} \) is 1, same as parent function) and open upwards.

To graph, we can also take points from the parent function, apply the shifts:

  • For example, a point on \( y = x^{2} \) like \( (1,1) \): shift 4 right: \( x=1 + 4=5 \), shift 5 up: \( y = 1+5 = 6 \), so the point \( (5,6) \) is on \( y=(x - 4)^{2}+5 \).
  • Another point \( (- 1,1) \) on \( y = x^{2} \): shift 4 right: \( x=-1 + 4 = 3 \), shift 5 up: \( y=1 + 5=6 \), so \( (3,6) \) is on the new graph.
  • The vertex is \( (4,5) \), so plotting the vertex and these shifted points (and others) will give the graph of \( y=(x - 4)^{2}+5 \).

Answer:

To graph \( y=(x - 4)^{2}+5 \), shift the graph of \( y = x^{2} \) (vertex at \((0,0)\), opening up) 4 units to the right and 5 units up. The new vertex is \((4,5)\), and the parabola has the same shape as \( y = x^{2} \) (opens upwards). Points from the parent function can be shifted (e.g., \((1,1)\) on \( y = x^{2} \) becomes \((5,6)\) on \( y=(x - 4)^{2}+5 \), \((-1,1)\) becomes \((3,6)\)) to help plot the graph, with the vertex at \((4,5)\) and opening upwards.