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graph $x < 5$. how do i graph the inequality?

Question

graph $x < 5$.
how do i graph the inequality?

Explanation:

Step1: Analyze the inequality symbol

The inequality is \( x < 5 \). The "less than" symbol (\(<\)) means that \( x \) can take any value strictly less than 5, so 5 is not included in the solution set. For a number line graph, we use an open circle at the boundary value (5) to indicate that the value is not included.

Step2: Determine the direction of the line

Since \( x \) is less than 5, the solutions are all the numbers to the left of 5 on the number line. So we draw a line extending to the left from the open circle at 5.

Step3: Correct the initial graph (if needed)

In the given initial graph, there is a green dot at -5 (which is not relevant for \( x < 5 \)) and the circle at 5 is not open (it seems to be a closed dot or a different mark). So we need to:

  1. Remove the green dot at -5 (or ignore it as it's not part of the correct graph for \( x < 5 \)).
  2. Make the circle at 5 open (to show 5 is not included).
  3. Draw the line from the open circle at 5 towards the left (since \( x < 5 \) means values less than 5, which are to the left on the number line).

Answer:

To graph \( x < 5 \):

  1. Place an open circle at \( 5 \) on the number line (since \( 5 \) is not a solution, as \( x < 5 \) means \( x \) cannot equal \( 5 \)).
  2. Draw a line (or an arrow) extending to the left from the open circle at \( 5 \) (since all numbers less than \( 5 \) lie to the left of \( 5 \) on the number line).

In the provided graph, you should:

  • Click "Make circle open" to change the circle at \( 5 \) to an open circle (removing the closed dot appearance).
  • Ensure the line/arrow points to the left (toward values less than \( 5 \)), not involving the -5 dot (which is irrelevant here).