Question

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an isotope has an atomic number of 51 and contains 70 neutrons. construct the symbol for the isotope.
tap on the parts of the symbol to enter or change the contents.

Explanation:

Step1: Find the mass number

The mass number ($A$) is the sum of the atomic number ($Z$) and the number of neutrons ($n$). Given $Z = 51$ and $n = 70$, so $A=Z + n=51 + 70 = 121$.

Step2: Identify the element

The atomic number 51 corresponds to the element Antimony (Sb). Wait, but in the given symbol template, it's "El", maybe a typo or maybe the element is Antimony. The isotope symbol is written as $^A_Z\text{X}$, where $X$ is the element symbol. So with $A = 121$, $Z = 51$, and $X=\text{Sb}$ (Antimony), but in the template, if we consider the given "El" as maybe a placeholder, but actually the element with atomic number 51 is Antimony (Sb). So the symbol should be $^{121}_{51}\text{Sb}$. But looking at the template, the top number is mass number, bottom is atomic number, and the element symbol. So top: 121, bottom: 51, element symbol: Sb (but in the template it's "El", maybe a mistake, but following the calculation, mass number is 121, atomic number 51, element is Sb (Antimony)).

Answer:

The isotope symbol is $\boldsymbol{^{121}_{51}\text{Sb}}$ (top number: 121, bottom number: 51, element symbol: Sb).