Question

1. how many grams of barium chloride are present in 4.08 moles of this compound? grams. 2. how many moles of barium chloride are present in 4.69 grams of this compound? moles. use the references to access important values if needed for this question. 3 more group attempts remaining

Explanation:

Step1: Calculate molar mass of barium chloride ($BaCl_2$)

The molar mass of $Ba$ is approximately 137.33 g/mol and of $Cl$ is approximately 35.45 g/mol. For $BaCl_2$, molar mass $M=137.33 + 2\times35.45=137.33 + 70.9 = 208.23$ g/mol.

Step2: Solve for mass in 1st question

We know that $n = 4.08$ moles and $M = 208.23$ g/mol. Using the formula $m=n\times M$, we have $m = 4.08\times208.23=4.08\times208.23 = 850.57$ g.

Step3: Solve for moles in 2nd question

We know that $m = 4.69$ g and $M = 208.23$ g/mol. Using the formula $n=\frac{m}{M}$, we have $n=\frac{4.69}{208.23}\approx0.0225$ moles.

Answer:

1. 850.57 grams
2. 0.0225 moles