Question

how many grams of sucrose (molecular weight = 342 g mole - 1) would you dissolve in water to make a total volume of 1 l of solution to produce a 0.22 m solution? ______ g
type your numeric answer and submit

unanswered

lab 4: q4
how many grams of sucrose (molecular weight = 342 g mole - 1) would you dissolve in water to make a total volume of 100 ml of solution to produce a 0.22 mm solution? ______ g
type your numeric answer and submit

Explanation:

Step1: Calculate moles of sucrose for first case

Use the formula $n = M\times V$, where $M$ is molarity and $V$ is volume. For a $0.22\ M$ solution with $V = 1\ L$, $n_1=0.22\ mol/L\times1\ L = 0.22\ mol$. Then, use $m = n\times MW$ (molecular - weight), so $m_1=0.22\ mol\times342\ g/mol = 75.24\ g$.

Step2: Calculate moles of sucrose for second case

First, convert volume to liters: $V_2 = 100\ mL=0.1\ L$ and molarity $M_2 = 0.22\ mM = 0.22\times10^{- 3}\ mol/L$. Then, $n_2 = M_2\times V_2=0.22\times10^{-3}\ mol/L\times0.1\ L = 2.2\times10^{-5}\ mol$. Using $m = n\times MW$, $m_2=2.2\times10^{-5}\ mol\times342\ g/mol=0.007524\ g$.

Answer:

75.24
0.007524