Question

how many moles are in 12 g of potassium permanganate (kmno₄)? report your final answer with the correct number of significant figures. the answer for each letter includes a number and its unit. there is a space between the number and its unit. use the following abreviations: mole = mol; grams = g
w/x x/y = z
w = x = y = z =
blank 1:
blank 2:
blank 3:
blank 4:

Explanation:

Step1: Calculate molar mass of KMnO₄

The molar mass of K (potassium) is approximately 39.1 g/mol, Mn (manganese) is approximately 54.9 g/mol, and O (oxygen) is approximately 16.0 g/mol. For KMnO₄, there is 1 K, 1 Mn and 4 O atoms. So molar mass $M = 39.1+54.9 + 4\times16.0=158.0$ g/mol.

Step2: Use mole - mass formula

The formula to calculate the number of moles $n$ is $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass. Here, $m = 12$ g and $M=158.0$ g/mol. In the given formula $\frac{W}{1}\times\frac{X}{Y}=Z$, $W$ is the mass, $X = 1$ (mole - mole conversion factor), $Y$ is the molar mass and $Z$ is the number of moles. So $W = 12$ g, $X = 1$ mol, $Y=158.0$ g, $Z=\frac{12}{158.0}\text{mol}\approx0.076$ mol.

Answer:

Blank 1: 12 g
Blank 2: 1 mol
Blank 3: 158.0 g
Blank 4: 0.076 mol