Question

how many moles is 573.28 g of agcl?
a. 5 mol
b. 4 mol
c. 2 mol
d. 3 mol

Explanation:

Step1: Calculate molar mass of AgCl

The molar mass of Ag (silver) is approximately 107.87 g/mol and Cl (chlorine) is approximately 35.45 g/mol. So, the molar mass of AgCl, $M = 107.87+35.45=143.32$ g/mol.

Step2: Calculate number of moles

The formula for number of moles $n=\frac{m}{M}$, where $m = 573.28$ g and $M = 143.32$ g/mol. So, $n=\frac{573.28}{143.32}=4$ mol.

Answer:

B. 4 mol