Question

how many particles are there in 2.46 moles of potassium chlorate, kcl?
in the first box select the correct amount, in the second box select the correct unit.
options for amount: 1.47×10²⁴, 4.06×10²⁴, 9.03×10²⁴, 2.46×10²⁴
options for unit: atoms, formula units, molecules, moles

Explanation:

Step1: Recall Avogadro's number

Avogadro's number is \( 6.022\times 10^{23} \) formula units per mole. To find the number of formula units in a given number of moles, we use the formula: Number of formula units \( = \) moles \( \times \) Avogadro's number.

Step2: Calculate the number of formula units

We are given 2.46 moles of KCl. So, we multiply the number of moles by Avogadro's number:
\( 2.46\space mol\times6.022\times 10^{23}\space \frac{\text{formula units}}{\text{mol}} \)
First, multiply 2.46 and 6.022:
\( 2.46\times6.022 = 2.46\times6 + 2.46\times0.022=14.76+ 0.05412 = 14.81412 \)
Then, multiply by \( 10^{23} \):
\( 14.81412\times 10^{23}=1.481412\times 10^{24}\approx1.47\times 10^{24} \) (after rounding appropriately)
The unit for the amount of KCl particles (formula units) here is formula units since KCl is an ionic compound and we count formula units.

Answer:

The correct amount is \( 1.47\times 10^{24} \) and the correct unit is formula units. So in the first box: \( 1.47\times 10^{24} \), in the second box: formula units.