Question

how would you prepare 80.0 ml of 0.800 m hno₃ from a stock solution of 4.00 m hno₃? what volume (in ml) of the 4.00 m hno₃ solution will you need? be sure your answer has the correct number of significant digits.

Explanation:

Step1: Recall dilution formula

The dilution formula is \( C_1V_1 = C_2V_2 \), where \( C_1 \) is the initial concentration, \( V_1 \) is the initial volume, \( C_2 \) is the final concentration, and \( V_2 \) is the final volume.

Step2: Identify known values

We know \( C_1 = 4.00 \, \text{M} \), \( C_2 = 0.800 \, \text{M} \), and \( V_2 = 80.0 \, \text{mL} \). We need to find \( V_1 \).

Step3: Rearrange formula to solve for \( V_1 \)

Rearranging the dilution formula gives \( V_1=\frac{C_2V_2}{C_1} \).

Step4: Substitute values into formula

Substituting the known values: \( V_1 = \frac{0.800 \, \text{M} \times 80.0 \, \text{mL}}{4.00 \, \text{M}} \).

Step5: Calculate the value

First, calculate the numerator: \( 0.800 \times 80.0 = 64.0 \). Then divide by the denominator: \( \frac{64.0}{4.00}=16.0 \, \text{mL} \).

Answer:

16.0